(-2)=4x^2+1

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Solution for (-2)=4x^2+1 equation: 



(-2)=4x^2+1

We move all terms to the left:

(-2)-(4x^2+1)=0

We add all the numbers together, and all the variables

-(4x^2+1)-2=0

We get rid of parentheses

-4x^2-1-2=0

We add all the numbers together, and all the variables

-4x^2-3=0

a = -4; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-4)·(-3)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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